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ign_ex1

Example of Chamber Pressure Calculation due to Igniter Charge Combustion

 

Consider the rocket motor and igniter shown in the figure above (dimensions are inches).

The motor chamber volume is Vc = p/4 (3) 2 (12) = 85 in3

And the grain volume is Vg = p/4 (2.75 2 - 1 2 ) 11 = 57 in3

Therefore the free volume is V = 85 - 57 = 28 in3

The igniter volume is Vi = p/4 (0.5) 2 (2) = 0.39 in3

The charge material is Black Powder (non-commercial grade) with an impetus of 75000 ft-lbf / lbm

and has a mass density of 0.057 lbm / in3

Charge mass is C = 0.057 (0.39) = 0.022 lbm

Loading density is D = 0.022 / 28 = 1 / 1273 lbm / in3

Let G = 1 since we are interested only in the maximum pressure that results from the charge combustion

The ambient pressure is Pa = 14.7 psia

The effective force is l = 75000 (12) = 900 000 in-lbf / lbm

This gives the resulting chamber pressure of


Last updated

Last updated July 1, 1999

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