Example 1 – Check structural strength of Xi rocket nosecone for two loading conditions:
1. Handling load
2. Flight load at Mach 1.0 velocity
at 10-degree angle-of-attack
Nosecone Description
The
Xi nosecone has a tangent-ogive profile.
The base diameter is 3.0 inches and length 7.56 inches giving a fineness ratio
of 2.52 . The nosecone is CAD designed and 3D printed of grey PLA plastic. The
nosecone houses a Big Red Bee BRB900 (900 MHz) GPS
transmitter in a shock-resistant cradle. The nosecone is designed for minimum
mass. Maximum expected velocity in flight is 1.0 Mach. The figure below
illustrates the nosecone design, which incorporates a shoulder for attachment
to the rocket body tube utilizing three #6-32 flat-head alloy-steel screws. A
minimum Safety Factor of 2.0 is the requirement for acceptable strength.
Xi nosecone with cutaway view on right
1. Handling condition
The
handling load condition is shown below. A force is applied at the tip of the
nosecone, perpendicular to the long-axis. This lateral force (F HANDLING)
is reacted at the nosecone shoulder (R) by bearing against the body tube. The
offset-moment (M) is reacted by the screws attaching the shoulder to the rocket
body.
Examining
the nosecone cross-section, it can be seen that there are two possible
“critical sections” where fracture may occur, labeled as A-A and B-B. Section
A-A is considered as this is the thinnest part of the nosecone wall at the
furthest distance from the applied load. Section B-B is considered as this
location is furthest from the applied load and where the reactions occur.
Dimensions to these two critical sections are shown in the figure below:
Based
on the dimensions of the nosecone cross-section at these two sections, the
pertinent geometric property, section modulus,
is calculated.
At section A-A:
Outer
diameter (Do) = 2.86 inch with wall thickness 0.050 inch, giving
Inside
diameter (Di)= 2.76 inch
Section
modulus =
At section B-B: (location
of screws attaching nosecone to rocket body)
Outer
diameter (Do) = 2.93 inch with wall thickness 0.080 inch, giving
Inside
diameter (Di)= 2.77 inch
Section
modulus =
The
magnitude of the handling load is next calculated, followed by the bending
stress at each section, and the resulting minimum Safety Factor.
Mass
of Xi rocket = 7.7 lbs (typical), apply 10%
growth factor:
m
= 1.10 × 7.7 = 8.48 lbs
Conservatively
take handling load as 5×m:
F
HANDLING = 5 × 8.48 = 42.4 lbf
Bending
moment at section A-A and B-B:
M
A-A = 42.4 × 5.71 = 242.1 lbf-in
M
B-B = 42.4 × 7.88 = 334.1 lbf-in
Bending
stress at section A-A and B-B
where
fb
A-A = 242.1/0.305 = 794
lbf/in2
fb
B-B = 334.1/0.497 = 672
lbf/in2
Section A-A is more critical than section B-B for
this loading condition.
The
nosecone is 3D printed of PLA plastic. Properties are given below:
PLA
Ref.https://www.makeitfrom.com/material-properties/Polylactic-Acid-PLA-Polylactide
Glass transition temperature = 60C.
Max. temperature mechanical = 50C.
Melting onset = 160C.
Thermal conductivity = 0.13 W/m-K
Density = 1.3 g/cc
E = 0.51x10^6 psi
elogation at break = 6%
Flexural modulus = 0.58x10^6 psi
Flexural strength = 12 ksi
Shear modulus = 0.35x10^6 psi
Tensile strength = 7.3 ksi
The
applicable property for this failure mode is tensile
strength . The strength properties indicated are for virgin PLA
filament. Three knockdown factors should be
applied:
1. Printing process deficiencies. Loading
direction is perpedicular to extrusion direction, relying upon heat fusion to
bond layers. Layed-down material dimensions may not match blueprint. Apply knockdown
factor of 20%
2. Environment. PLA aborbs moisture and may
weaken in service. Apply knockdown factor of 20%
3. Pigment. Natural PLA (no dye added) has
the highest strength. Pigments tend to reduce strength [1] . Apply
knockdown factor of 5%.
Factored
tensile strength:
S
tf = 7300 × (1.0 – 0.20) × (1.0 – 0.20) × (1.0 – 0.05) = 4438 lbf/in2
Minimum Safety Factor based on Handling Load condition:
S.F. = 4438/794 = 5.59 >
2.0
[1] Ref. “The Effects of PLA Color on Material
Properties of 3-D Printed Components”, Ben Wittbrodt and Joshua M. Pearce,
Michigan Technological University, Houghton, MI 49931, USA
2. Flight Condition: Mach 1.0
velocity at 10-degree angle-of-attack
The
Xi nosecone subjected to this flight
condition is illustrated below. The nosecone is subjected to drag load (FD)
assumed acting at the tip, and a lateral load (NNose) acting at the
nosecone Centre of Pressure. The angle-of-attack (a) is indicated. Assume this condition
occurs at an altitude of 2500 feet ASL.
The
drag load is calculated first:
Air
density (r) is found from the following table:
https://www.engineeringtoolbox.com/standard-atmosphere-d_604.html
By
linear interpolation, at 2500 feet ASL, r = 0.0022 slugs/ft3
The
critical flight condition is 1.0 Mach. From the following table, the velocity
is found:
https://www.engineersedge.com/physics/speed_of_sound_13241.htm
By
linear interpolation, at 2500 feet ASL, V = 754.5 mph = 1107 ft/sec.
The
drag coefficient, at small angle-of-attack, for a tangent-ogive nosecone with
fineness ratio 2.52 is found using AeroLab
software:
To
be conservative, the maximum value (at 1.1 Mach) is taken:
Cdn = 0.26 frictional drag is neglected as tiny
The
base area of the nosecone is:
A
= ¼ p (3.0/12)2 = 0.049 ft2
The
drag force is calculated:
The
next step is to calculate the normal force acting on the nosecone, given by:
NNOSE
= q A a (CNa)N
The dynamic
pressure (q) is calculated:
q
= ½ (0.0022) (1107)2 = 1348 lbf/ft2
The
angle-of-attack of 10° is converted to radians:
a = 10/180 × p = 0.175 radian
The
slope of the normal force coefficient with respect to angle-of-attack (CNa)N is obtained from Figure 7
which is reproduced below:
The
peak value at Mach 1.1 is conervatively chosen:
(CNa)N = 2.3 per radian, therefore:
NNOSE
= 1348 (0.049) 0.175 (2.3) = 26.6 lbf
The
location of the nosecone C.P. is found using Figure 8, reproduced below:
At
Mach 1.0, for a fineness ratio of 2.5, XCP = 1.2 calibres aft of the
nosecone tip. As the calibre of the nosecone is 3.0 inches, the C.P. location
is 1.2 × 3.0 = 3.6 inches aft of the tip.
These
two loading conditions are applied to the nosecone as shown in the figure
below. Critical sections A-A and B-B are checked for bending stress and
resulting Safety Factor determined.
To
simplify the analysis, the drag force is resolved into two components, one
axial and one lateral:
FD
ax = 17.2 cos 10° = 16.9 lbf
FD
lat = 17.2 sin 10° = 3.0 lbf
The
axial component of the drag force is conservatively neglected, as it tends to
put the critical sections in compression, which is not a critical failure mode.
Bending
moment at section A-A and B-B:
M
A-A = 3.0 × 5.71+ 26.6 × 2.11 = 73.3 lbf-in
M
B-B = 3.0 × 7.88+ 26.6 × 4.28
= 137.5 lbf-in
Bending
stress at section A-A and B-B
where
fb
A-A = 73.3/0.305 = 240 lbf/in2
fb
B-B = 137.5/0.497 = 277
lbf/in2
Both Section A-A and section B-B are less critical
for this loading condition than the Handling condition.
Important – consistent units must be used in all calculations. For
example, when calculating FD, q, and NNOSE
, imperial units or SI (metric) should be:
Mass slugs (kilograms)
Force lbf (Newtons)
Length feet (metres)
Angle radians (radians)
Time seconds (seconds)
Other consistent units may be used;
however, the above systems are recommended.
Rev.2023/07/21